高数积分,题目如图 谢谢!

2025-05-23 14:50:37
推荐回答(2个)
回答1:

回答2:

设x=sint,t∈[π/4,π/2],原式=∫(
π/4,π/2)csc^2t-1dt=-cott-t(π/4,π/2)=π/4+1-π/2=1-π/4