解原式=[(x+2)/(x-2)(x+2)-(2x-5)/(x-2)²]×(x-2)/(x-3)=[1/(x-2)-(2x-5)/(x-2)²]×(x-2)/(x-3)=1/(x-3)-(2x-5)/(x-2)(x-3)=(x-2)/(x-2)(x-3)-(2x-5)/(x-2)(x-3)=(x-2-2x+5)/(x-2)(x-3)=(-x+3)/(x-2)(x-3)=-1/(x-2)
