设y等于1比x加2倍根号x则dy等于多少

2025-06-20 19:17:09
推荐回答(1个)
回答1:

y=1/(x+2√x)
所以求微分得到
dy=d[1/(x+2√x)]
= -1/(x+2√x)^2 *d(x+2√x)
= -1/(x+2√x)^2 * (1+1/√x) dx