设f(x+x⼀1)=x^2+x^2⼀1,求f(x)

2025-05-22 19:51:10
推荐回答(2个)
回答1:

f (x + 1/x) = x² + 1/x² = (x + 1/x)² - 2
∵x+1/x ≠ 0
∴令t = x+1/x ≠ 0
f(t)=t²-2≠0 (t≠0)
即:f(x)=x²-2 (x≠0)

回答2:

f(x+x/1)=x^2+x^2/1
=(x+x/1)^2-2
f(x)=x^2-2