(2010?宣武区一模)有A、B两个由不同材料制成的实心正方体,它们的重力分别为GA、GB,密度分别为ρA、ρ

2025-05-20 08:27:42
推荐回答(1个)
回答1:

(1)∵B物体边长是A物体边长的2倍,
∴B物体底面积与A物体底面积之比为:SA:SB=1:4,
B物体体积与A物体体积之比为:VA:VB=1:8.
∵A叠放于B正上方置于水平桌面上,根据A对B 的压强与B对桌面的压强相等,

GA
SA
=
GA+GB
SB

GA
GA+GB
=
1
4

GA
GB
=
1
3
,故选项D错误.
GA
GB
=
ρAgVA
ρBgVB
=
ρA
ρB
×
VA
VB
=
ρA
ρB
×
1
8
=
1
3

ρA
ρB
=
8
3
,故选项B错误.
(2)
η1
η2
=
GAhA
(GA+G甲动)hA
GBhB
(GB+G乙动)hB
=
GA
GB
×
GB+G乙动
GA+G甲动
=
GA
GB
×
3GA+3G甲动
GA+G甲动
=
1
3
×
3
1
=
1
1
,故选项A正确.
(3)
P1
P2
=
(GA+G甲动)hA
t
(GB+G乙动)hB
t
=
GA+G甲动
GB+G乙动
×
hA
hB
=
GA+G甲动
3GA+3G甲动
×
hA
hB
=
1
3
×
5
2
=
5
6
,故选项C错误.
故选A.