解方程:(1)(2x+1)2=3(2x+1);(2)x2-8x-5=0

解方程:(1)(2x+1)2=3(2x+1);(2)x2-8x-5=0.
2025-06-21 10:37:19
推荐回答(1个)
回答1:

(1)(2x+1)2=3(2x+1),
(2x+1)2-3(2x+1)=0,
(2x+1)(2x+1-3)=0,
2x+1=0,2x+1-3=0,
x1=-

1
2
,x2=1;

(2)x2-8x-5=0,
b2-4ac=(-8)2-4×1×(-5)=84,
x=
84
2

x1=4+
21
,x2=4-
21