设方程4x2-7x-3=0的两个根为x1、x2,求下列各式的值:(1)(x1-3)(x2-3); &nbsp...

2025-05-20 02:07:22
推荐回答(1个)
回答1:

根据题意得x1+x2=

7
4
,x1x2=-
3
4

(1)原式=x1x2-3(x1+x2)+9=-
3
4
-3×
7
4
+9=3;
(2)原式=
x12+x22
x1x2
=
(x1+x2)2?2x1x2
x1x2
=
(
7
4
)2?2×(?
3
4
)
?
3
4
=-
73
12