将下列多项式因式分解:(1)a3-2a2b+ab2(2)(a2+6a)2+18(a2+6a)+81

2025-06-20 14:17:58
推荐回答(1个)
回答1:

(1)原式=a(a2-2ab+b2
=a(a-b)2

(2)(a2+6a)2+18(a2+6a)+81
=(a2+6a+9)2
=[(a+3)2]2
=(a+3)4