2log[3](2)-log[3](32/9)+log[3](8)-5^(log[5](3))
=log[3](2^2/32*9*8)-3
=log[3](9)-3
=2-3
=-1
注:方括号内为对数之底
2log(3)2-log(3)32/9+log(3)8-5^log(5)3
=2log(3)2-log(3)2^5+log(3)9+log(3)2^3-3
=2log(3)2-5log(3)2+log(3)3^2+3log(3)2-3
=2-3
=-1
2log(3)2-log(3)32/9+log(3)8-5^log(5)3
=log(3)[4/(32/9)*8]-3
=log(3)9-3
=2-3
=-1
题目请补充完整 几次访?
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