初一数学先化简再求值:4x눀y-[6xy-3(4xy-2)-x눀y]+1,其中x=2,y=-1⼀2

2025-05-19 15:34:49
推荐回答(4个)
回答1:

4x²y-[6xy-3(4xy-2)-x²y] 1
= 4x²y-(6xy-12xy 6- x²y) 1
=4x²y-(-6xy-x²y 6) 1
=5x²y 6xy-5
代入得等于11

回答2:

4x²y-[6xy-3(4xy-2)-x²y]+1
=4x²y-6xy+12xy-6+x²y+1
=3x²y+6xy-5
=3X2²X(-1/2)+6X2X(-1/2)-5
=-17

回答3:

化简后原式=xy(5x+6)-5
代入x=2,y=1/2
可得原式=11

回答4:

最笨方法解还是简便?