答案没错就是C，b>a>1比如b=9,a=3,log(a,3)=1,log(b,3)=1/2
log(a,3)>log(b,3)>0,{log(a,3)>0,log(a,3)=log(3,3)/log(3,a)=1/log(3,a)>0,a>1;同理b>1}
log(a,3)-log(b,3)>0,
log(10,3)-log(10,a)-[log(10,3)-log(10,b)]>0
log(10,b)-log(10,a)>0
log(10,b/a)>0
b/a>1,
b>a>1
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