已知x+y=6.xy=7。求(3x+y)^2+(x+3y)^2的值

2025-06-20 14:08:22
推荐回答(3个)
回答1:

(x+y)^2=36
X^2+Y^2+2XY=36
2XY=14
X^2+Y^2=22
X^2+Y^2-2XY=22-14=8
(X-Y)^2=8
X-Y=2*2^0.5(二根号二)
因为X+Y=6
所以X=3+2^0.5
y=3-2^0.5
最后带进去算吧。。。

回答2:

x²+y²=(x+y)²-2xy=22
(3x+y)^2+(x+3y)^2

= 9x²+6xy+y² + x²+6xy+9y²
=10(x²+y²)+12xy
=220+84=304

回答3:

(3x+y)^2+(x+3y)^2
=9x^2+6xy+y^2+x^2+6xy+9y^2
=10x^2+10y^2+12xy
=10(x^2+y^2)+12xy
=10(x^2+y^2+2xy)+12xy-10*2xy
=10(x+y)^2-8xy
=10*6^2-8*7
=360-56
=304