解：x^7+x^5+1=(x^2+x+1)(x^5-x^4+x^3-x+1)分析：x^7+x^5+1除以x^3-1余数得x^2+x+1因为x^3-1=(x-1)(x^2+x+1)提公因式x^2+x+1得：x^7+x^5+1=(x^2+x+1)(x^5-x^4+x^3-x+1)
x^7+x^5+1=(x^2+x+1)(x^5-x^4+x^3-x+1)
