设m>n>0,x=根号(m⼀n)+根号(n⼀m),化简a=(2*根号(x^2-4))⼀(x-根号(

2025-06-21 21:38:42
推荐回答(1个)
回答1:

将x的值代入A得
A=2{√(√m/n+√n/m)]^2-4}/[x-√(√m/n+√n/m)^2)-4]
=2√(m/n+n/m+2-4)/[√m/n+√n/m-√(m/n+n/m+2-4)]
=2√(m/n+n/m-2)/[√m/n+√n/m-√(m/n+n/m-2)]
分子分母同乘以√mn,且m>0, n>0
=2√(m-n)^2/(m+n+√(m-n)^2)
m》n
=2(m-n) /(m+n-(m-n))
=(m-n)/n