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2025-05-23 13:53:18
推荐回答(2个)
回答1:

如图

回答2:

x+y+z=e^z
dx +dy +dz = e^z. dz
(e^z -1 ) dz = dx +dy
dz = (dx +dy)/(e^z -1 )
= (dx +dy)/(x+y+z -1 )