(1)原式=|-2 3 |+1-3× 3 3 =2 3 +1- 3 = 3 +1;(2)原式= a?2 (a+1)(a?1) ÷ a2?1?2a+1 a+1 = a?2 (a+1)(a?1) ÷ a(a?2) a+1 = a?2 (a+1)(a?1) ? a+1 a(a?2) = 1 a2?a ,∵a是方程2x2-2x-7=0的根,∴a2-a= 7 2 ,∴原式= 2 7 .