log9(9右下角小写)5=a换底:以3为底[log3(3右下角小写)5]/[log3(3右下角小写)9]=a[log3(3右下角小写)5]=[log3(3右下角小写)9]*a=2a___(1)同理,[log3(3右下角小写)7]=2b___(2)(1)+(2)[log3(3右下角小写)5]+[log3(3右下角小写)7]=2a+2b即:log3(3右下角小写)35=2a+2b
a+b
(a+b)/2