c=2√2
2a=6
a=3
b=√(a^2-c^2)=√(9-8)=1
椭圆标准方程
x^2/9+y^2=1
已知过点(0,2)且斜率为1的直线为
y-2=1*(x-0)
y=x+2代入椭圆方程得
x^2/9+(x+2)^2=1
x^2+9(x^2+4x+4)=9
10x^2+36x+27=0
xa+xb=-36/10=-18/5
xaxb=27/10
(xa-xb)^2=(xa+xb)^2-4xaxb
=324/25-4*27/10
=(324-270)/25
=54/25
(ya-yb)^2=(xa+2-xb-2)^2=(xa-xb)^2=54/25
ab=√[(xa-xb)^2+(ya-yb)^2]
=√(54/25+54/25)
=√(108/25)
=6√3 /5