解：如图，过点C作CG∥AB，∵AB∥ED，∴AB∥CG∥ED，∴∠BCG=∠ABC=30°，∠DCG=∠CDE=68°，∴∠BCD=∠BCG+∠DCG=30°+68°=98°，∵CF平分∠BCD，∴∠FCD= 1 2 ∠BCD= 1 2 ×98°=49°．
