这道基本不等式的题怎么做?

2025-05-23 14:45:20
推荐回答(3个)
回答1:

如下图所示,这题用换元法

回答2:

回答3:

(a-c)[1/(a-b)+1/(b-c)]
=[(a-b)+(b-c)][1/(a-b)+1/(b-c)]
=2+[(b-c)/(a-b)+(a-b)/(b-c)]≥4,
∴4≤(a-c)[1/(a-b)+1/(b-c)]