裂项法,1/(n^2-1)=1/(n+1)(n-1)=1/2*(1/(n-1)-1/(n+1)1/3+1/8+1/15+……+1/120=1/2*[(1-1/3)+(1/3-1/5)+(1/5-1/7)+……+(1/10-1/12)]=1/2*[1-1/12]=11/24
1/3+1/8+1/15+1/24+1/35=1/2×(1-1/3+1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7)=1/2×(1+1/2-1/6-1/7)=1/2×25/21=25/42
好难